311420012343131 has 2 divisors, whose sum is σ = 311420012343132. Its totient is φ = 311420012343130.

The previous prime is 311420012343103. The next prime is 311420012343133. The reversal of 311420012343131 is 131343210024113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311420012343131 - 2¹⁰ = 311420012342107 is a prime.

It is a super-2 number, since 2×311420012343131² (a number of 30 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 311420012343133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 311420012343094 and 311420012343103.

It is not a weakly prime, because it can be changed into another prime (311420012343133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155710006171565 + 155710006171566.

It is an arithmetic number, because the mean of its divisors is an integer number (155710006171566).

Almost surely, 2^{311420012343131} is an apocalyptic number.

311420012343131 is a deficient number, since it is larger than the sum of its proper divisors (1).

311420012343131 is an equidigital number, since it uses as much as digits as its factorization.

311420012343131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 311420012343131 its reverse (131343210024113), we get a palindrome (442763222367244).

The spelling of 311420012343131 in words is "three hundred eleven trillion, four hundred twenty billion, twelve million, three hundred forty-three thousand, one hundred thirty-one".