131343210024113 has 4 divisors (see below), whose sum is σ = 139069281202020. Its totient is φ = 123617138846208.

The previous prime is 131343210024007. The next prime is 131343210024119. The reversal of 131343210024113 is 311420012343131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 36491349211249 + 94851860812864 = 6040807^2 + 9739192^2 .

It is a cyclic number.

It is not a de Polignac number, because 131343210024113 - 2¹⁴ = 131343210007729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131343210024119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3863035588928 + ... + 3863035588961.

It is an arithmetic number, because the mean of its divisors is an integer number (34767320300505).

Almost surely, 2^{131343210024113} is an apocalyptic number.

It is an amenable number.

131343210024113 is a deficient number, since it is larger than the sum of its proper divisors (7726071177907).

131343210024113 is an equidigital number, since it uses as much as digits as its factorization.

131343210024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7726071177906.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131343210024113 its reverse (311420012343131), we get a palindrome (442763222367244).

The spelling of 131343210024113 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred ten million, twenty-four thousand, one hundred thirteen".