Base | Representation |
---|---|
bin | 100011011001111000010101… |
… | …1110001001101101111010111 |
3 | 1111211122111000210100111022202 |
4 | 1012303300223301031233113 |
5 | 311304302104043114431 |
6 | 3022200250405315115 |
7 | 122411240303463401 |
oct | 10663605361155727 |
9 | 1454574023314282 |
10 | 311420223019991 |
11 | 90256636205a98 |
12 | 2ab173aa705a9b |
13 | 1049ca54ac9007 |
14 | 56c8b67d0bb71 |
15 | 2600b4c0328cb |
hex | 11b3c2bc4dbd7 |
311420223019991 has 2 divisors, whose sum is σ = 311420223019992. Its totient is φ = 311420223019990.
The previous prime is 311420223019987. The next prime is 311420223020009. The reversal of 311420223019991 is 199910322024113.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 311420223019991 - 22 = 311420223019987 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311420223019091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155710111509995 + 155710111509996.
It is an arithmetic number, because the mean of its divisors is an integer number (155710111509996).
Almost surely, 2311420223019991 is an apocalyptic number.
311420223019991 is a deficient number, since it is larger than the sum of its proper divisors (1).
311420223019991 is an equidigital number, since it uses as much as digits as its factorization.
311420223019991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 47.
The spelling of 311420223019991 in words is "three hundred eleven trillion, four hundred twenty billion, two hundred twenty-three million, nineteen thousand, nine hundred ninety-one".
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