Base | Representation |
---|---|
bin | 1001000100000100101… |
… | …00010011000000000111 |
3 | 1002202211200012120021012 |
4 | 10202002110103000013 |
5 | 20100244021112403 |
6 | 355022145112435 |
7 | 31333243233632 |
oct | 4420224230007 |
9 | 1082750176235 |
10 | 311424004103 |
11 | 11008a805703 |
12 | 5043332871b |
13 | 234a0850654 |
14 | 11104464c19 |
15 | 817a5a3ed8 |
hex | 4882513007 |
311424004103 has 4 divisors (see below), whose sum is σ = 311579796000. Its totient is φ = 311268212208.
The previous prime is 311424004051. The next prime is 311424004117. The reversal of 311424004103 is 301400424113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301400424113 = 83 ⋅3631330411.
It is a cyclic number.
It is not a de Polignac number, because 311424004103 - 212 = 311424000007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311424004153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77892950 + ... + 77896947.
It is an arithmetic number, because the mean of its divisors is an integer number (77894949000).
Almost surely, 2311424004103 is an apocalyptic number.
311424004103 is a deficient number, since it is larger than the sum of its proper divisors (155791897).
311424004103 is a wasteful number, since it uses less digits than its factorization.
311424004103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155791896.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 311424004103 its reverse (301400424113), we get a palindrome (612824428216).
The spelling of 311424004103 in words is "three hundred eleven billion, four hundred twenty-four million, four thousand, one hundred three".
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