311430001201321 has 2 divisors, whose sum is σ = 311430001201322. Its totient is φ = 311430001201320.

The previous prime is 311430001201303. The next prime is 311430001201327. The reversal of 311430001201321 is 123102100034113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 236390471250025 + 75039529951296 = 15374995^2 + 8662536^2 .

It is an emirp because it is prime and its reverse (123102100034113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311430001201321 - 2²³ = 311429992812713 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311430001201292 and 311430001201301.

It is not a weakly prime, because it can be changed into another prime (311430001201327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715000600660 + 155715000600661.

It is an arithmetic number, because the mean of its divisors is an integer number (155715000600661).

Almost surely, 2^{311430001201321} is an apocalyptic number.

It is an amenable number.

311430001201321 is a deficient number, since it is larger than the sum of its proper divisors (1).

311430001201321 is an equidigital number, since it uses as much as digits as its factorization.

311430001201321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 311430001201321 its reverse (123102100034113), we get a palindrome (434532101235434).

The spelling of 311430001201321 in words is "three hundred eleven trillion, four hundred thirty billion, one million, two hundred one thousand, three hundred twenty-one".