Base | Representation |
---|---|
bin | 100011011001111100111001… |
… | …0100110000001000010101111 |
3 | 1111211200102021020201120110001 |
4 | 1012303321302212001002233 |
5 | 311304432120301420302 |
6 | 3022204544545525131 |
7 | 122412034515605611 |
oct | 10663716246010257 |
9 | 1454612236646401 |
10 | 311430001201327 |
11 | 9025a7a3795398 |
12 | 2ab192793437a7 |
13 | 104a0952860028 |
14 | 56c941480cdb1 |
15 | 26010206c6787 |
hex | 11b3e729810af |
311430001201327 has 2 divisors, whose sum is σ = 311430001201328. Its totient is φ = 311430001201326.
The previous prime is 311430001201321. The next prime is 311430001201331. The reversal of 311430001201327 is 723102100034113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311430001201327 - 27 = 311430001201199 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311430001201295 and 311430001201304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311430001201321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715000600663 + 155715000600664.
It is an arithmetic number, because the mean of its divisors is an integer number (155715000600664).
Almost surely, 2311430001201327 is an apocalyptic number.
311430001201327 is a deficient number, since it is larger than the sum of its proper divisors (1).
311430001201327 is an equidigital number, since it uses as much as digits as its factorization.
311430001201327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
The spelling of 311430001201327 in words is "three hundred eleven trillion, four hundred thirty billion, one million, two hundred one thousand, three hundred twenty-seven".
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