311430011214340 has 12 divisors (see below), whose sum is σ = 654003023550156. Its totient is φ = 124572004485728.

The previous prime is 311430011214299. The next prime is 311430011214349. The reversal of 311430011214340 is 43412110034113.

It can be written as a sum of positive squares in 2 ways, for example, as 161155560426436 + 150274450787904 = 12694706^2 + 12258648^2 .

It is a super-2 number, since 2×311430011214340² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311430011214299 and 311430011214308.

It is not an unprimeable number, because it can be changed into a prime (311430011214349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7785750280339 + ... + 7785750280378.

It is an arithmetic number, because the mean of its divisors is an integer number (54500251962513).

Almost surely, 2^{311430011214340} is an apocalyptic number.

It is an amenable number.

311430011214340 is an abundant number, since it is smaller than the sum of its proper divisors (342573012335816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311430011214340 is a wasteful number, since it uses less digits than its factorization.

311430011214340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15571500560726 (or 15571500560724 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 311430011214340 its reverse (43412110034113), we get a palindrome (354842121248453).

The spelling of 311430011214340 in words is "three hundred eleven trillion, four hundred thirty billion, eleven million, two hundred fourteen thousand, three hundred forty".