311431003340381 has 2 divisors, whose sum is σ = 311431003340382. Its totient is φ = 311431003340380.

The previous prime is 311431003340357. The next prime is 311431003340383. The reversal of 311431003340381 is 183043300134113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 304943621143225 + 6487382197156 = 17462635^2 + 2547034^2 .

It is a cyclic number.

It is not a de Polignac number, because 311431003340381 - 2¹⁴ = 311431003323997 is a prime.

It is a super-2 number, since 2×311431003340381² (a number of 30 digits) contains 22 as substring.

Together with 311431003340383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311431003340383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715501670190 + 155715501670191.

It is an arithmetic number, because the mean of its divisors is an integer number (155715501670191).

Almost surely, 2^{311431003340381} is an apocalyptic number.

It is an amenable number.

311431003340381 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431003340381 is an equidigital number, since it uses as much as digits as its factorization.

311431003340381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 35.

Adding to 311431003340381 its reverse (183043300134113), we get a palindrome (494474303474494).

The spelling of 311431003340381 in words is "three hundred eleven trillion, four hundred thirty-one billion, three million, three hundred forty thousand, three hundred eighty-one".