311431010134440 has 256 divisors, whose sum is σ = 1104662292480000. Its totient is φ = 68734537482240.

The previous prime is 311431010134429. The next prime is 311431010134603. The reversal of 311431010134440 is 44431010134113.

It is a super-2 number, since 2×311431010134440² (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 311431010134398 and 311431010134407.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1626210 + ... + 25010129.

It is an arithmetic number, because the mean of its divisors is an integer number (4315087080000).

Almost surely, 2^{311431010134440} is an apocalyptic number.

311431010134440 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311431010134440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (552331146240000).

311431010134440 is an abundant number, since it is smaller than the sum of its proper divisors (793231282345560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311431010134440 is a wasteful number, since it uses less digits than its factorization.

311431010134440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26636840 (or 26636836 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 311431010134440 its reverse (44431010134113), we get a palindrome (355862020268553).

The spelling of 311431010134440 in words is "three hundred eleven trillion, four hundred thirty-one billion, ten million, one hundred thirty-four thousand, four hundred forty".