311431322314111 has 2 divisors, whose sum is σ = 311431322314112. Its totient is φ = 311431322314110.

The previous prime is 311431322314109. The next prime is 311431322314117. The reversal of 311431322314111 is 111413223134113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311431322314111 - 2¹ = 311431322314109 is a prime.

Together with 311431322314109, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311431322314117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715661157055 + 155715661157056.

It is an arithmetic number, because the mean of its divisors is an integer number (155715661157056).

Almost surely, 2^{311431322314111} is an apocalyptic number.

311431322314111 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431322314111 is an equidigital number, since it uses as much as digits as its factorization.

311431322314111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 31.

Adding to 311431322314111 its reverse (111413223134113), we get a palindrome (422844545448224).

The spelling of 311431322314111 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred twenty-two million, three hundred fourteen thousand, one hundred eleven".