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31143143231 is a prime number
BaseRepresentation
bin11101000000010001…
…101010011100111111
32222101102022121002022
4131000101222130333
51002240121040411
622150145350355
72151520230644
oct350021523477
988342277068
1031143143231
1112231546502
1260519383bb
132c24170205
1417161b7dcb
15c24182edb
hex74046a73f

31143143231 has 2 divisors, whose sum is σ = 31143143232. Its totient is φ = 31143143230.

The previous prime is 31143143221. The next prime is 31143143233. The reversal of 31143143231 is 13234134113.

It is a strong prime.

It is an emirp because it is prime and its reverse (13234134113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31143143231 - 26 = 31143143167 is a prime.

It is a super-2 number, since 2×311431432312 (a number of 22 digits) contains 22 as substring.

Together with 31143143233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31143143231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31143143233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571571615 + 15571571616.

It is an arithmetic number, because the mean of its divisors is an integer number (15571571616).

Almost surely, 231143143231 is an apocalyptic number.

31143143231 is a deficient number, since it is larger than the sum of its proper divisors (1).

31143143231 is an equidigital number, since it uses as much as digits as its factorization.

31143143231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 26.

Adding to 31143143231 its reverse (13234134113), we get a palindrome (44377277344).

The spelling of 31143143231 in words is "thirty-one billion, one hundred forty-three million, one hundred forty-three thousand, two hundred thirty-one".