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3114320013232 = 241711449705931
BaseRepresentation
bin101101010100011011111…
…100000010011110110000
3102000201121022112122220021
4231110123330002132300
5402011111410410412
610342410542053224
7441000516223231
oct55243374023660
912021538478807
103114320013232
11aa085950375a
124236ab57a214
131978aa03574c
14aaa3bb33088
1556025c25607
hex2d51bf027b0

3114320013232 has 20 divisors (see below), whose sum is σ = 6388935910056. Its totient is φ = 1465562359040.

The previous prime is 3114320013209. The next prime is 3114320013313. The reversal of 3114320013232 is 2323100234113.

3114320013232 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 3114320013197 and 3114320013206.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5724852694 + ... + 5724853237.

Almost surely, 23114320013232 is an apocalyptic number.

It is an amenable number.

3114320013232 is an abundant number, since it is smaller than the sum of its proper divisors (3274615896824).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3114320013232 is a wasteful number, since it uses less digits than its factorization.

3114320013232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11449705956 (or 11449705950 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3114320013232 its reverse (2323100234113), we get a palindrome (5437420247345).

The spelling of 3114320013232 in words is "three trillion, one hundred fourteen billion, three hundred twenty million, thirteen thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 17 34 68 136 272 11449705931 22899411862 45798823724 91597647448 183195294896 194645000827 389290001654 778580003308 1557160006616 3114320013232