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31143231113110 = 253114323111311
BaseRepresentation
bin1110001010011000110010…
…01110100100011110010110
311002021021010022201121122021
413011030121032210132112
513040222314131104420
6150123000341323354
76363011204460334
oct705143116443626
9132237108647567
1031143231113110
119a178520741a6
1235ab92510655a
13144ba4281010c
147994aa1c8b54
15390190c587aa
hex1c53193a4796

31143231113110 has 8 divisors (see below), whose sum is σ = 56057816003616. Its totient is φ = 12457292445240.

The previous prime is 31143231113047. The next prime is 31143231113149. The reversal of 31143231113110 is 1131113234113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×311432311131102 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1557161555646 + ... + 1557161555665.

It is an arithmetic number, because the mean of its divisors is an integer number (7007227000452).

Almost surely, 231143231113110 is an apocalyptic number.

31143231113110 is a deficient number, since it is larger than the sum of its proper divisors (24914584890506).

31143231113110 is a wasteful number, since it uses less digits than its factorization.

31143231113110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3114323111318.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 31143231113110 its reverse (1131113234113), we get a palindrome (32274344347223).

The spelling of 31143231113110 in words is "thirty-one trillion, one hundred forty-three billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred ten".

Divisors: 1 2 5 10 3114323111311 6228646222622 15571615556555 31143231113110