Base | Representation |
---|---|
bin | 11101000000010010… |
… | …010011001100101111 |
3 | 2222101102122002000122 |
4 | 131000102103030233 |
5 | 1002240141411002 |
6 | 22150153115155 |
7 | 2151521524346 |
oct | 350022231457 |
9 | 88342562018 |
10 | 31143310127 |
11 | 1223164a936 |
12 | 60519b8abb |
13 | 2c241cb177 |
14 | 171621cb5d |
15 | c241b76a2 |
hex | 74049332f |
31143310127 has 2 divisors, whose sum is σ = 31143310128. Its totient is φ = 31143310126.
The previous prime is 31143310097. The next prime is 31143310139. The reversal of 31143310127 is 72101334113.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (72101334113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31143310127 - 212 = 31143306031 is a prime.
It is a super-2 number, since 2×311433101272 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31143310096 and 31143310105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31143310027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15571655063 + 15571655064.
It is an arithmetic number, because the mean of its divisors is an integer number (15571655064).
Almost surely, 231143310127 is an apocalyptic number.
31143310127 is a deficient number, since it is larger than the sum of its proper divisors (1).
31143310127 is an equidigital number, since it uses as much as digits as its factorization.
31143310127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
The spelling of 31143310127 in words is "thirty-one billion, one hundred forty-three million, three hundred ten thousand, one hundred twenty-seven".
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