3114403314143 has 4 divisors (see below), whose sum is σ = 3397530888168. Its totient is φ = 2831275740120.

The previous prime is 3114403314137. The next prime is 3114403314151. The reversal of 3114403314143 is 3414133044113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3114403314143 - 2²⁰ = 3114402265567 is a prime.

It is a super-3 number, since 3×3114403314143³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114403314173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141563786996 + ... + 141563787017.

It is an arithmetic number, because the mean of its divisors is an integer number (849382722042).

Almost surely, 2^{3114403314143} is an apocalyptic number.

3114403314143 is a deficient number, since it is larger than the sum of its proper divisors (283127574025).

3114403314143 is a wasteful number, since it uses less digits than its factorization.

3114403314143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283127574024.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 3114403314143 its reverse (3414133044113), we get a palindrome (6528536358256).

The spelling of 3114403314143 in words is "three trillion, one hundred fourteen billion, four hundred three million, three hundred fourteen thousand, one hundred forty-three".