Base | Representation |
---|---|
bin | 1110001010011010011011… |
… | …01011001110011001101111 |
3 | 11002021100101122110112120012 |
4 | 13011031031223032121233 |
5 | 13040231114411240421 |
6 | 150123223533243435 |
7 | 6363042050644226 |
oct | 705151553163157 |
9 | 132240348415505 |
10 | 31144111040111 |
11 | 9a181638363a3 |
12 | 35abb2b93357b |
13 | 144bb52bc9094 |
14 | 799550ddbcbd |
15 | 3901e311c95b |
hex | 1c534dace66f |
31144111040111 has 2 divisors, whose sum is σ = 31144111040112. Its totient is φ = 31144111040110.
The previous prime is 31144111040093. The next prime is 31144111040117. The reversal of 31144111040111 is 11104011144113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31144111040111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31144111040117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15572055520055 + 15572055520056.
It is an arithmetic number, because the mean of its divisors is an integer number (15572055520056).
Almost surely, 231144111040111 is an apocalyptic number.
31144111040111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31144111040111 is an equidigital number, since it uses as much as digits as its factorization.
31144111040111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 23.
Adding to 31144111040111 its reverse (11104011144113), we get a palindrome (42248122184224).
The spelling of 31144111040111 in words is "thirty-one trillion, one hundred forty-four billion, one hundred eleven million, forty thousand, one hundred eleven".
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