Base | Representation |
---|---|
bin | 1110001010011011001010… |
… | …00110110000110111101111 |
3 | 11002021101102001010211120202 |
4 | 13011031211012300313233 |
5 | 13040232421024311101 |
6 | 150123330534504115 |
7 | 6363054563130011 |
oct | 705154506606757 |
9 | 132241361124522 |
10 | 31144504135151 |
11 | 9a18345715530 |
12 | 35b001b50503b |
13 | 144bbb64907b4 |
14 | 79958b2c61b1 |
15 | 3902178ba36b |
hex | 1c53651b0def |
31144504135151 has 4 divisors (see below), whose sum is σ = 33975822692904. Its totient is φ = 28313185577400.
The previous prime is 31144504135139. The next prime is 31144504135207. The reversal of 31144504135151 is 15153140544113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31144504135151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31144504135651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1415659278860 + ... + 1415659278881.
It is an arithmetic number, because the mean of its divisors is an integer number (8493955673226).
Almost surely, 231144504135151 is an apocalyptic number.
31144504135151 is a deficient number, since it is larger than the sum of its proper divisors (2831318557753).
31144504135151 is a wasteful number, since it uses less digits than its factorization.
31144504135151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2831318557752.
The product of its (nonzero) digits is 72000, while the sum is 38.
Adding to 31144504135151 its reverse (15153140544113), we get a palindrome (46297644679264).
The spelling of 31144504135151 in words is "thirty-one trillion, one hundred forty-four billion, five hundred four million, one hundred thirty-five thousand, one hundred fifty-one".
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