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3115204268800 = 285213149251291
BaseRepresentation
bin101101010101010000101…
…001001101001100000000
3102000210212221102111111111
4231111100221031030000
5402014414243100200
610343034410453104
7441031444245631
oct55252051151400
912023787374444
103115204268800
11aa1172661a88
124238b7734194
131979bb2a89b0
14aaac3351888
15560786920ba
hex2d550a4d300

3115204268800 has 216 divisors, whose sum is σ = 8359504801200. Its totient is φ = 1142505062400.

The previous prime is 3115204268753. The next prime is 3115204268893. The reversal of 3115204268800 is 88624025113.

It is a super-3 number, since 3×31152042688003 (a number of 38 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (40).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12271155 + ... + 12522445.

Almost surely, 23115204268800 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3115204268800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4179752400600).

3115204268800 is an abundant number, since it is smaller than the sum of its proper divisors (5244300532400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3115204268800 is a wasteful number, since it uses less digits than its factorization.

3115204268800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 251479 (or 251460 counting only the distinct ones).

The product of its (nonzero) digits is 92160, while the sum is 40.

The spelling of 3115204268800 in words is "three trillion, one hundred fifteen billion, two hundred four million, two hundred sixty-eight thousand, eight hundred".