Base | Representation |
---|---|
bin | 101101010101010010110… |
… | …011000010110011000011 |
3 | 102000210222110102021002102 |
4 | 231111102303002303003 |
5 | 402020003020331430 |
6 | 10343042141141015 |
7 | 441032363340602 |
oct | 55252263026303 |
9 | 12023873367072 |
10 | 3115240402115 |
11 | aa1190aa1526 |
12 | 42390785a76b |
13 | 1979c591a55a |
14 | aaac8079a39 |
15 | 5607b92d345 |
hex | 2d552cc2cc3 |
3115240402115 has 4 divisors (see below), whose sum is σ = 3738288482544. Its totient is φ = 2492192321688.
The previous prime is 3115240402103. The next prime is 3115240402117. The reversal of 3115240402115 is 5112040425113.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3115240402115 - 28 = 3115240401859 is a prime.
It is a super-3 number, since 3×31152404021153 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3115240402117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311524040207 + ... + 311524040216.
It is an arithmetic number, because the mean of its divisors is an integer number (934572120636).
Almost surely, 23115240402115 is an apocalyptic number.
3115240402115 is a deficient number, since it is larger than the sum of its proper divisors (623048080429).
3115240402115 is an equidigital number, since it uses as much as digits as its factorization.
3115240402115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 623048080428.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 3115240402115 its reverse (5112040425113), we get a palindrome (8227280827228).
The spelling of 3115240402115 in words is "three trillion, one hundred fifteen billion, two hundred forty million, four hundred two thousand, one hundred fifteen".
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