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312000413100979 is a prime number
BaseRepresentation
bin100011011110000110100000…
…1110010101110101110110011
31111220200221121020100101122211
41012330031001302232232303
5311343303321223212404
63023323002220312551
7122501200043010451
oct10674150162565663
91456627536311584
10312000413100979
119045a6a53a8199
122abab92b0a2757
1310512688572145
145708c872299d1
152610ca7b7eb04
hex11bc341caebb3

312000413100979 has 2 divisors, whose sum is σ = 312000413100980. Its totient is φ = 312000413100978.

The previous prime is 312000413100977. The next prime is 312000413101019. The reversal of 312000413100979 is 979001314000213.

It is an a-pointer prime, because the next prime (312000413101019) can be obtained adding 312000413100979 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 312000413100979 - 21 = 312000413100977 is a prime.

Together with 312000413100977, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (312000413100977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000206550489 + 156000206550490.

It is an arithmetic number, because the mean of its divisors is an integer number (156000206550490).

Almost surely, 2312000413100979 is an apocalyptic number.

312000413100979 is a deficient number, since it is larger than the sum of its proper divisors (1).

312000413100979 is an equidigital number, since it uses as much as digits as its factorization.

312000413100979 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 40.

The spelling of 312000413100979 in words is "three hundred twelve trillion, four hundred thirteen million, one hundred thousand, nine hundred seventy-nine".