312001144341041 has 2 divisors, whose sum is σ = 312001144341042. Its totient is φ = 312001144341040.

The previous prime is 312001144341031. The next prime is 312001144341043. The reversal of 312001144341041 is 140143441100213.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189412048917025 + 122589095424016 = 13762705^2 + 11071996^2 .

It is a cyclic number.

It is not a de Polignac number, because 312001144341041 - 2²² = 312001140146737 is a prime.

Together with 312001144341043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 312001144340995 and 312001144341013.

It is not a weakly prime, because it can be changed into another prime (312001144341043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000572170520 + 156000572170521.

It is an arithmetic number, because the mean of its divisors is an integer number (156000572170521).

Almost surely, 2^{312001144341041} is an apocalyptic number.

It is an amenable number.

312001144341041 is a deficient number, since it is larger than the sum of its proper divisors (1).

312001144341041 is an equidigital number, since it uses as much as digits as its factorization.

312001144341041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 312001144341041 its reverse (140143441100213), we get a palindrome (452144585441254).

The spelling of 312001144341041 in words is "three hundred twelve trillion, one billion, one hundred forty-four million, three hundred forty-one thousand, forty-one".