Base | Representation |
---|---|
bin | 100011011110000110111111… |
… | …0011111010100110101010101 |
3 | 1111220201001020012111120200220 |
4 | 1012330031332133110311111 |
5 | 311343312412421034331 |
6 | 3023323251234424553 |
7 | 122501234216425311 |
oct | 10674157637246525 |
9 | 1456631205446626 |
10 | 312001431424341 |
11 | 904600781a664a |
12 | 2ababb74132159 |
13 | 105127bb526549 |
14 | 5708d42586b41 |
15 | 2610d17280296 |
hex | 11bc37e7d4d55 |
312001431424341 has 8 divisors (see below), whose sum is σ = 429421324971264. Its totient is φ = 201291246080160.
The previous prime is 312001431424339. The next prime is 312001431424343. The reversal of 312001431424341 is 143424134100213.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (312001431424339) and next prime (312001431424343).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 312001431424341 - 21 = 312001431424339 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312001431424343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1677427050576 + ... + 1677427050761.
It is an arithmetic number, because the mean of its divisors is an integer number (53677665621408).
Almost surely, 2312001431424341 is an apocalyptic number.
312001431424341 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
It is an amenable number.
312001431424341 is a deficient number, since it is larger than the sum of its proper divisors (117419893546923).
312001431424341 is a wasteful number, since it uses less digits than its factorization.
312001431424341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3354854101371.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 312001431424341 its reverse (143424134100213), we get a palindrome (455425565524554).
The spelling of 312001431424341 in words is "three hundred twelve trillion, one billion, four hundred thirty-one million, four hundred twenty-four thousand, three hundred forty-one".
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