312002540550055 has 4 divisors (see below), whose sum is σ = 374403048660072. Its totient is φ = 249602032440040.

The previous prime is 312002540550017. The next prime is 312002540550067. The reversal of 312002540550055 is 550055045200213.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 312002540550055 - 2¹⁵ = 312002540517287 is a prime.

It is a super-4 number, since 4×312002540550055⁴ (a number of 59 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312002540549996 and 312002540550023.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31200254055001 + ... + 31200254055010.

It is an arithmetic number, because the mean of its divisors is an integer number (93600762165018).

Almost surely, 2^{312002540550055} is an apocalyptic number.

312002540550055 is a deficient number, since it is larger than the sum of its proper divisors (62400508110017).

312002540550055 is an equidigital number, since it uses as much as digits as its factorization.

312002540550055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62400508110016.

The product of its (nonzero) digits is 150000, while the sum is 37.

Adding to 312002540550055 its reverse (550055045200213), we get a palindrome (862057585750268).

The spelling of 312002540550055 in words is "three hundred twelve trillion, two billion, five hundred forty million, five hundred fifty thousand, fifty-five".