3120124013 has 2 divisors, whose sum is σ = 3120124014. Its totient is φ = 3120124012.

The previous prime is 3120124009. The next prime is 3120124031. The reversal of 3120124013 is 3104210213.

Together with next prime (3120124031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2456391844 + 663732169 = 49562^2 + 25763^2 .

It is a cyclic number.

It is not a de Polignac number, because 3120124013 - 2² = 3120124009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3120123982 and 3120124000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3120124003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560062006 + 1560062007.

It is an arithmetic number, because the mean of its divisors is an integer number (1560062007).

Almost surely, 2^3120124013 is an apocalyptic number.

It is an amenable number.

3120124013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3120124013 is an equidigital number, since it uses as much as digits as its factorization.

3120124013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 3120124013 is about 55858.0702584685. The cubic root of 3120124013 is about 1461.2480747437.

Adding to 3120124013 its reverse (3104210213), we get a palindrome (6224334226).

The spelling of 3120124013 in words is "three billion, one hundred twenty million, one hundred twenty-four thousand, thirteen".