312012433114343 has 8 divisors (see below), whose sum is σ = 336175793301600. Its totient is φ = 287872273469088.

The previous prime is 312012433114243. The next prime is 312012433114411. The reversal of 312012433114343 is 343411334210213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 312012433114343 - 2¹⁰ = 312012433113319 is a prime.

It is a super-2 number, since 2×312012433114343² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312012433114243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5800107563 + ... + 5800161356.

It is an arithmetic number, because the mean of its divisors is an integer number (42021974162700).

Almost surely, 2^{312012433114343} is an apocalyptic number.

312012433114343 is a deficient number, since it is larger than the sum of its proper divisors (24163360187257).

312012433114343 is a wasteful number, since it uses less digits than its factorization.

312012433114343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11600271001.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 312012433114343 its reverse (343411334210213), we get a palindrome (655423767324556).

The spelling of 312012433114343 in words is "three hundred twelve trillion, twelve billion, four hundred thirty-three million, one hundred fourteen thousand, three hundred forty-three".