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312013111200 = 25352729640421
BaseRepresentation
bin1001000101001010110…
…11100011111110100000
31002211100201201022021120
410202211123203332200
520103000324024300
6355200431452240
731353655454220
oct4424533437640
91084321638246
10312013111200
111103622a357a
1250578687080
132356590412b
141115c7b4080
1581b216e3a0
hex48a56e3fa0

312013111200 has 288 divisors, whose sum is σ = 1200714399360. Its totient is φ = 68857958400.

The previous prime is 312013111199. The next prime is 312013111231. The reversal of 312013111200 is 2111310213.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 312013111200.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 166990 + ... + 807410.

It is an arithmetic number, because the mean of its divisors is an integer number (4169147220).

Almost surely, 2312013111200 is an apocalyptic number.

312013111200 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312013111200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (600357199680).

312013111200 is an abundant number, since it is smaller than the sum of its proper divisors (888701288160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312013111200 is a wasteful number, since it uses less digits than its factorization.

312013111200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 640480 (or 640467 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 312013111200 its reverse (2111310213), we get a palindrome (314124421413).

The spelling of 312013111200 in words is "three hundred twelve billion, thirteen million, one hundred eleven thousand, two hundred".