Base | Representation |
---|---|
bin | 101101011001111010011… |
… | …010110101100000000011 |
3 | 102001021210002222122011222 |
4 | 231121322122311200003 |
5 | 402110132212042011 |
6 | 10345222233025255 |
7 | 441266316231554 |
oct | 55317232654003 |
9 | 12037702878158 |
10 | 3120200112131 |
11 | aa32a6690023 |
12 | 42487085522b |
13 | 1983063105cb |
14 | ab038a5032b |
15 | 5626c076ddb |
hex | 2d67a6b5803 |
3120200112131 has 2 divisors, whose sum is σ = 3120200112132. Its totient is φ = 3120200112130.
The previous prime is 3120200112103. The next prime is 3120200112181. The reversal of 3120200112131 is 1312110020213.
3120200112131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3120200112131 is a prime.
It is a super-2 number, since 2×31202001121312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3120200112181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560100056065 + 1560100056066.
It is an arithmetic number, because the mean of its divisors is an integer number (1560100056066).
Almost surely, 23120200112131 is an apocalyptic number.
3120200112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120200112131 is an equidigital number, since it uses as much as digits as its factorization.
3120200112131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 3120200112131 its reverse (1312110020213), we get a palindrome (4432310132344).
The spelling of 3120200112131 in words is "three trillion, one hundred twenty billion, two hundred million, one hundred twelve thousand, one hundred thirty-one".
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