312024113 has 4 divisors (see below), whose sum is σ = 312908388. Its totient is φ = 311139840.

The previous prime is 312024077. The next prime is 312024127. The reversal of 312024113 is 311420213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311420213 = 13 ⋅23955401.

It can be written as a sum of positive squares in 2 ways, for example, as 61340224 + 250683889 = 7832^2 + 15833^2 .

It is a cyclic number.

It is not a de Polignac number, because 312024113 - 2¹² = 312020017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312024091 and 312024100.

It is not an unprimeable number, because it can be changed into a prime (312024133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 441608 + ... + 442313.

It is an arithmetic number, because the mean of its divisors is an integer number (78227097).

Almost surely, 2^312024113 is an apocalyptic number.

It is an amenable number.

312024113 is a deficient number, since it is larger than the sum of its proper divisors (884275).

312024113 is an equidigital number, since it uses as much as digits as its factorization.

312024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 884274.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 312024113 is about 17664.2042843713. The cubic root of 312024113 is about 678.2597608625.

Adding to 312024113 its reverse (311420213), we get a palindrome (623444326).

The spelling of 312024113 in words is "three hundred twelve million, twenty-four thousand, one hundred thirteen".