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31203020121023 is a prime number
BaseRepresentation
bin1110001100001000001001…
…11011100010001110111111
311002110222110010021220122202
413012010010323202032333
513042212241122333043
6150210245231302115
76400225632606632
oct706040473421677
9132428403256582
1031203020121023
119a40143440833
1235bb43037a93b
1314545806349ca
1479c33ca37c19
153919debd01b8
hex1c6104ee23bf

31203020121023 has 2 divisors, whose sum is σ = 31203020121024. Its totient is φ = 31203020121022.

The previous prime is 31203020121019. The next prime is 31203020121079. The reversal of 31203020121023 is 32012102030213.

It is a weak prime.

It is an emirp because it is prime and its reverse (32012102030213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31203020121023 - 22 = 31203020121019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31203020120986 and 31203020121004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31203020171023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601510060511 + 15601510060512.

It is an arithmetic number, because the mean of its divisors is an integer number (15601510060512).

Almost surely, 231203020121023 is an apocalyptic number.

31203020121023 is a deficient number, since it is larger than the sum of its proper divisors (1).

31203020121023 is an equidigital number, since it uses as much as digits as its factorization.

31203020121023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 31203020121023 its reverse (32012102030213), we get a palindrome (63215122151236).

The spelling of 31203020121023 in words is "thirty-one trillion, two hundred three billion, twenty million, one hundred twenty-one thousand, twenty-three".