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312030201302221 is a prime number
BaseRepresentation
bin100011011110010100011000…
…1010011101100110011001101
31111220210210111020002210202111
41012330220301103230303031
5311344300323013132341
63023344410125024021
7122503303161361303
oct10674506123546315
91456723436083674
10312030201302221
11904712a102a726
122abb56630b5011
1310515424aab71c
14570a4b14a0273
15261194cdbd681
hex11bca314ecccd

312030201302221 has 2 divisors, whose sum is σ = 312030201302222. Its totient is φ = 312030201302220.

The previous prime is 312030201302189. The next prime is 312030201302243. The reversal of 312030201302221 is 122203102030213.

It is an a-pointer prime, because the next prime (312030201302243) can be obtained adding 312030201302221 to its sum of digits (22).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 311782009022500 + 248192279721 = 17657350^2 + 498189^2 .

It is an emirp because it is prime and its reverse (122203102030213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312030201302221 - 25 = 312030201302189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312030201302192 and 312030201302201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312030201302251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156015100651110 + 156015100651111.

It is an arithmetic number, because the mean of its divisors is an integer number (156015100651111).

Almost surely, 2312030201302221 is an apocalyptic number.

It is an amenable number.

312030201302221 is a deficient number, since it is larger than the sum of its proper divisors (1).

312030201302221 is an equidigital number, since it uses as much as digits as its factorization.

312030201302221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 312030201302221 its reverse (122203102030213), we get a palindrome (434233303332434).

The spelling of 312030201302221 in words is "three hundred twelve trillion, thirty billion, two hundred one million, three hundred two thousand, two hundred twenty-one".