Base | Representation |
---|---|
bin | 1110001100010101001001… |
… | …11110011101110001101011 |
3 | 11002111122110120120020002122 |
4 | 13012022210332131301223 |
5 | 13042321040023223201 |
6 | 150213402015021455 |
7 | 6400563620443424 |
oct | 706124476356153 |
9 | 132448416506078 |
10 | 31210000211051 |
11 | 9a430a5526782 |
12 | 3600859b0a88b |
13 | 14551237894ac |
14 | 79c801a9064b |
15 | 391c9c8b4e1b |
hex | 1c62a4f9dc6b |
31210000211051 has 2 divisors, whose sum is σ = 31210000211052. Its totient is φ = 31210000211050.
The previous prime is 31210000211023. The next prime is 31210000211053. The reversal of 31210000211051 is 15011200001213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31210000211051 - 210 = 31210000210027 is a prime.
It is a super-2 number, since 2×312100002110512 (a number of 28 digits) contains 22 as substring.
Together with 31210000211053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31210000211053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605000105525 + 15605000105526.
It is an arithmetic number, because the mean of its divisors is an integer number (15605000105526).
Almost surely, 231210000211051 is an apocalyptic number.
31210000211051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31210000211051 is an equidigital number, since it uses as much as digits as its factorization.
31210000211051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 31210000211051 its reverse (15011200001213), we get a palindrome (46221200212264).
The spelling of 31210000211051 in words is "thirty-one trillion, two hundred ten billion, two hundred eleven thousand, fifty-one".
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