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31210000211051 is a prime number
BaseRepresentation
bin1110001100010101001001…
…11110011101110001101011
311002111122110120120020002122
413012022210332131301223
513042321040023223201
6150213402015021455
76400563620443424
oct706124476356153
9132448416506078
1031210000211051
119a430a5526782
123600859b0a88b
1314551237894ac
1479c801a9064b
15391c9c8b4e1b
hex1c62a4f9dc6b

31210000211051 has 2 divisors, whose sum is σ = 31210000211052. Its totient is φ = 31210000211050.

The previous prime is 31210000211023. The next prime is 31210000211053. The reversal of 31210000211051 is 15011200001213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31210000211051 - 210 = 31210000210027 is a prime.

It is a super-2 number, since 2×312100002110512 (a number of 28 digits) contains 22 as substring.

Together with 31210000211053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (31210000211053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605000105525 + 15605000105526.

It is an arithmetic number, because the mean of its divisors is an integer number (15605000105526).

Almost surely, 231210000211051 is an apocalyptic number.

31210000211051 is a deficient number, since it is larger than the sum of its proper divisors (1).

31210000211051 is an equidigital number, since it uses as much as digits as its factorization.

31210000211051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 31210000211051 its reverse (15011200001213), we get a palindrome (46221200212264).

The spelling of 31210000211051 in words is "thirty-one trillion, two hundred ten billion, two hundred eleven thousand, fifty-one".