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31211002032317 is a prime number
BaseRepresentation
bin1110001100010111000001…
…01100000111000010111101
311002111202001101200000111222
413012023200230013002331
513042330113010013232
6150214045243323125
76400630504001222
oct706134054070275
9132452041600458
1031211002032317
119a43569a83938
123600a995204a5
1314552531b3643
1479c898b53949
15391d0a805d12
hex1c62e0b070bd

31211002032317 has 2 divisors, whose sum is σ = 31211002032318. Its totient is φ = 31211002032316.

The previous prime is 31211002032313. The next prime is 31211002032319. The reversal of 31211002032317 is 71323020011213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28811247847321 + 2399754184996 = 5367611^2 + 1549114^2 .

It is a cyclic number.

It is not a de Polignac number, because 31211002032317 - 22 = 31211002032313 is a prime.

It is a super-2 number, since 2×312110020323172 (a number of 28 digits) contains 22 as substring.

Together with 31211002032319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31211002032313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605501016158 + 15605501016159.

It is an arithmetic number, because the mean of its divisors is an integer number (15605501016159).

Almost surely, 231211002032317 is an apocalyptic number.

It is an amenable number.

31211002032317 is a deficient number, since it is larger than the sum of its proper divisors (1).

31211002032317 is an equidigital number, since it uses as much as digits as its factorization.

31211002032317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 26.

The spelling of 31211002032317 in words is "thirty-one trillion, two hundred eleven billion, two million, thirty-two thousand, three hundred seventeen".