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31211020023 = 323021451921
BaseRepresentation
bin11101000100010100…
…100101111011110111
32222120011001002112120
4131010110211323313
51002410010120043
622201012251023
72153303202321
oct350424457367
988504032476
1031211020023
1112266897327
126070610a73
132c352474b1
141721206611
15c2a0de983
hex744525ef7

31211020023 has 8 divisors (see below), whose sum is σ = 41616593136. Its totient is φ = 20806396800.

The previous prime is 31211020019. The next prime is 31211020067. The reversal of 31211020023 is 32002011213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 31211020023 - 22 = 31211020019 is a prime.

It is a super-2 number, since 2×312110200232 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31211019984 and 31211020011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31211020003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 156898 + ... + 295023.

It is an arithmetic number, because the mean of its divisors is an integer number (5202074142).

Almost surely, 231211020023 is an apocalyptic number.

31211020023 is a deficient number, since it is larger than the sum of its proper divisors (10405573113).

31211020023 is a wasteful number, since it uses less digits than its factorization.

31211020023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 474945.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 31211020023 its reverse (32002011213), we get a palindrome (63213031236).

The spelling of 31211020023 in words is "thirty-one billion, two hundred eleven million, twenty thousand, twenty-three".

Divisors: 1 3 23021 69063 451921 1355763 10403673341 31211020023