Base | Representation |
---|---|
bin | 100011011110111001101110… |
… | …1100010110000111111010100 |
3 | 1111221002110111102202020202221 |
4 | 1012331303131202300333110 |
5 | 311402104044442002040 |
6 | 3023445312152512124 |
7 | 122512142451106555 |
oct | 10675633542607724 |
9 | 1457073442666687 |
10 | 312110400344020 |
11 | 904a2306324863 |
12 | 2b0091056ab644 |
13 | 1051cb66223645 |
14 | 571031c84c32c |
15 | 2613a93aa774a |
hex | 11bdcdd8b0fd4 |
312110400344020 has 48 divisors (see below), whose sum is σ = 656229772388736. Its totient is φ = 124692231312000.
The previous prime is 312110400344011. The next prime is 312110400344021. The reversal of 312110400344020 is 20443004011213.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312110400344021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 84173785 + ... + 87803455.
It is an arithmetic number, because the mean of its divisors is an integer number (13671453591432).
Almost surely, 2312110400344020 is an apocalyptic number.
It is an amenable number.
312110400344020 is an abundant number, since it is smaller than the sum of its proper divisors (344119372044716).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312110400344020 is a wasteful number, since it uses less digits than its factorization.
312110400344020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3634912 (or 3634910 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 312110400344020 its reverse (20443004011213), we get a palindrome (332553404355233).
The spelling of 312110400344020 in words is "three hundred twelve trillion, one hundred ten billion, four hundred million, three hundred forty-four thousand, twenty".
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