312111013114433 has 8 divisors (see below), whose sum is σ = 336141935398248. Its totient is φ = 288083288375424.

The previous prime is 312111013114403. The next prime is 312111013114451. The reversal of 312111013114433 is 334411310111213.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 3433416290704 + 308677596823729 = 1852948^2 + 17569223^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-312111013114433 is a prime.

It is a super-2 number, since 2×312111013114433² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312111013114396 and 312111013114405.

It is not an unprimeable number, because it can be changed into a prime (312111013114403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 799183466 + ... + 799573907.

It is an arithmetic number, because the mean of its divisors is an integer number (42017741924781).

Almost surely, 2^{312111013114433} is an apocalyptic number.

It is an amenable number.

312111013114433 is a deficient number, since it is larger than the sum of its proper divisors (24030922283815).

312111013114433 is a wasteful number, since it uses less digits than its factorization.

312111013114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1598772403.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 312111013114433 its reverse (334411310111213), we get a palindrome (646522323225646).

The spelling of 312111013114433 in words is "three hundred twelve trillion, one hundred eleven billion, thirteen million, one hundred fourteen thousand, four hundred thirty-three".