Base | Representation |
---|---|
bin | 101101011010110000110… |
… | …101001111010000000011 |
3 | 102001101010201202022001022 |
4 | 231122300311033100003 |
5 | 402114014412044021 |
6 | 10345453003300055 |
7 | 441331042540163 |
oct | 55326065172003 |
9 | 12041121668038 |
10 | 3121113003011 |
11 | aa3724a174a3 |
12 | 424a8651a62b |
13 | 19842049b623 |
14 | ab0c3da45a3 |
15 | 562c229d1ab |
hex | 2d6b0d4f403 |
3121113003011 has 2 divisors, whose sum is σ = 3121113003012. Its totient is φ = 3121113003010.
The previous prime is 3121113002933. The next prime is 3121113003013. The reversal of 3121113003011 is 1103003111213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3121113003011 - 210 = 3121113001987 is a prime.
It is a super-2 number, since 2×31211130030112 (a number of 26 digits) contains 22 as substring.
Together with 3121113003013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3121113003013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560556501505 + 1560556501506.
It is an arithmetic number, because the mean of its divisors is an integer number (1560556501506).
Almost surely, 23121113003011 is an apocalyptic number.
3121113003011 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121113003011 is an equidigital number, since it uses as much as digits as its factorization.
3121113003011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 3121113003011 its reverse (1103003111213), we get a palindrome (4224116114224).
The spelling of 3121113003011 in words is "three trillion, one hundred twenty-one billion, one hundred thirteen million, three thousand, eleven".
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