Base | Representation |
---|---|
bin | 101101011010110001110… |
… | …110000101001001010111 |
3 | 102001101011220201212212211 |
4 | 231122301312011021113 |
5 | 402114033240012413 |
6 | 10345454411454251 |
7 | 441331340164021 |
oct | 55326166051127 |
9 | 12041156655784 |
10 | 3121130000983 |
11 | aa3733577305 |
12 | 424a90157387 |
13 | 198423b704b7 |
14 | ab0c634b011 |
15 | 562c3a0983d |
hex | 2d6b1d85257 |
3121130000983 has 2 divisors, whose sum is σ = 3121130000984. Its totient is φ = 3121130000982.
The previous prime is 3121130000951. The next prime is 3121130001001. The reversal of 3121130000983 is 3890000311213.
It is a strong prime.
It is an emirp because it is prime and its reverse (3890000311213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3121130000983 - 25 = 3121130000951 is a prime.
It is a super-2 number, since 2×31211300009832 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3121130000903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560565000491 + 1560565000492.
It is an arithmetic number, because the mean of its divisors is an integer number (1560565000492).
Almost surely, 23121130000983 is an apocalyptic number.
3121130000983 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121130000983 is an equidigital number, since it uses as much as digits as its factorization.
3121130000983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 3121130000983 in words is "three trillion, one hundred twenty-one billion, one hundred thirty million, nine hundred eighty-three", and thus it is an aban number.
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