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3121130001001 is a prime number
BaseRepresentation
bin101101011010110001110…
…110000101001001101001
3102001101011220201212220111
4231122301312011021221
5402114033240013001
610345454411454321
7441331340164045
oct55326166051151
912041156655814
103121130001001
11aa3733577321
12424a901573a1
13198423b704cc
14ab0c634b025
15562c3a09851
hex2d6b1d85269

3121130001001 has 2 divisors, whose sum is σ = 3121130001002. Its totient is φ = 3121130001000.

The previous prime is 3121130000983. The next prime is 3121130001023. The reversal of 3121130001001 is 1001000311213.

3121130001001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3118049640000 + 3080361001 = 1765800^2 + 55501^2 .

It is a cyclic number.

It is not a de Polignac number, because 3121130001001 - 213 = 3121129992809 is a prime.

It is a super-2 number, since 2×31211300010012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3121130031001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560565000500 + 1560565000501.

It is an arithmetic number, because the mean of its divisors is an integer number (1560565000501).

Almost surely, 23121130001001 is an apocalyptic number.

It is an amenable number.

3121130001001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121130001001 is an equidigital number, since it uses as much as digits as its factorization.

3121130001001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 3121130001001 its reverse (1001000311213), we get a palindrome (4122130312214).

The spelling of 3121130001001 in words is "three trillion, one hundred twenty-one billion, one hundred thirty million, one thousand, one".