312115202511213 has 4 divisors (see below), whose sum is σ = 416153603348288. Its totient is φ = 208076801674140.

The previous prime is 312115202511181. The next prime is 312115202511221.

312115202511213 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 312115202511213 - 2⁵ = 312115202511181 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312115202511283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52019200418533 + ... + 52019200418538.

It is an arithmetic number, because the mean of its divisors is an integer number (104038400837072).

Almost surely, 2^{312115202511213} is an apocalyptic number.

It is an amenable number.

312115202511213 is a deficient number, since it is larger than the sum of its proper divisors (104038400837075).

312115202511213 is a wasteful number, since it uses less digits than its factorization.

312115202511213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104038400837074.

The product of its (nonzero) digits is 3600, while the sum is 30.

It can be divided in two parts, 31211520 and 2511213, that added together give a palindrome (33722733).

The spelling of 312115202511213 in words is "three hundred twelve trillion, one hundred fifteen billion, two hundred two million, five hundred eleven thousand, two hundred thirteen".