Base | Representation |
---|---|
bin | 1110001100011000111001… |
… | …11101011001001001111111 |
3 | 11002111211122212100110012011 |
4 | 13012030130331121021333 |
5 | 13042334200334232103 |
6 | 150214333444152051 |
7 | 6400664532516061 |
oct | 706143475311177 |
9 | 132454585313164 |
10 | 31212013195903 |
11 | 9a43a38832021 |
12 | 3601120098627 |
13 | 145538482bba7 |
14 | 79c953169731 |
15 | 391d6948ed6d |
hex | 1c631cf5927f |
31212013195903 has 2 divisors, whose sum is σ = 31212013195904. Its totient is φ = 31212013195902.
The previous prime is 31212013195841. The next prime is 31212013195907. The reversal of 31212013195903 is 30959131021213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31212013195903 - 237 = 31074574242431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31212013195907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606006597951 + 15606006597952.
It is an arithmetic number, because the mean of its divisors is an integer number (15606006597952).
Almost surely, 231212013195903 is an apocalyptic number.
31212013195903 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212013195903 is an equidigital number, since it uses as much as digits as its factorization.
31212013195903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 40.
The spelling of 31212013195903 in words is "thirty-one trillion, two hundred twelve billion, thirteen million, one hundred ninety-five thousand, nine hundred three".
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