Base | Representation |
---|---|
bin | 1110001100011001000100… |
… | …01001010101010110000111 |
3 | 11002111211212221002022222101 |
4 | 13012030202021111112013 |
5 | 13042334340123241403 |
6 | 150214350233212531 |
7 | 6400666640243446 |
oct | 706144211252607 |
9 | 132454787068871 |
10 | 31212100212103 |
11 | 9a43a82965638 |
12 | 3601145261147 |
13 | 1455399877975 |
14 | 79c96093ad5d |
15 | 391d71e2c71d |
hex | 1c6322255587 |
31212100212103 has 2 divisors, whose sum is σ = 31212100212104. Its totient is φ = 31212100212102.
The previous prime is 31212100212101. The next prime is 31212100212157. The reversal of 31212100212103 is 30121200121213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31212100212103 - 21 = 31212100212101 is a prime.
Together with 31212100212101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31212100212101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606050106051 + 15606050106052.
It is an arithmetic number, because the mean of its divisors is an integer number (15606050106052).
Almost surely, 231212100212103 is an apocalyptic number.
31212100212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212100212103 is an equidigital number, since it uses as much as digits as its factorization.
31212100212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31212100212103 its reverse (30121200121213), we get a palindrome (61333300333316).
The spelling of 31212100212103 in words is "thirty-one trillion, two hundred twelve billion, one hundred million, two hundred twelve thousand, one hundred three".
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