Base | Representation |
---|---|
bin | 1110001100011001000101… |
… | …10011001111111100101111 |
3 | 11002111211220200202120121021 |
4 | 13012030202303033330233 |
5 | 13042334400431400142 |
6 | 150214351304515011 |
7 | 6401000132526331 |
oct | 706144263177457 |
9 | 132454820676537 |
10 | 31212111200047 |
11 | 9a43a8908aa88 |
12 | 3601148a7ba67 |
13 | 145539bc240cb |
14 | 79c96219b451 |
15 | 391d72d9d267 |
hex | 1c6322ccff2f |
31212111200047 has 2 divisors, whose sum is σ = 31212111200048. Its totient is φ = 31212111200046.
The previous prime is 31212111199999. The next prime is 31212111200051. The reversal of 31212111200047 is 74000211121213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31212111200047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31212111199994 and 31212111200030.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31212111290047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606055600023 + 15606055600024.
It is an arithmetic number, because the mean of its divisors is an integer number (15606055600024).
Almost surely, 231212111200047 is an apocalyptic number.
31212111200047 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212111200047 is an equidigital number, since it uses as much as digits as its factorization.
31212111200047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
The spelling of 31212111200047 in words is "thirty-one trillion, two hundred twelve billion, one hundred eleven million, two hundred thousand, forty-seven".
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