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312122100131 = 2910762831039
BaseRepresentation
bin1001000101010111110…
…11010100100110100011
31002211122022210111222122
410202223323110212203
520103211224201011
6355215323454455
731356451035212
oct4425373244643
91084568714878
10312122100131
11110408874576
12505a908742b
132358237421a
141116d065079
1581bb9ec3db
hex48abed49a3

312122100131 has 4 divisors (see below), whose sum is σ = 322884931200. Its totient is φ = 301359269064.

The previous prime is 312122100119. The next prime is 312122100151. The reversal of 312122100131 is 131001221213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 312122100131 - 214 = 312122083747 is a prime.

It is a super-2 number, since 2×3121221001312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312122100151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5381415491 + ... + 5381415548.

It is an arithmetic number, because the mean of its divisors is an integer number (80721232800).

Almost surely, 2312122100131 is an apocalyptic number.

312122100131 is a deficient number, since it is larger than the sum of its proper divisors (10762831069).

312122100131 is a wasteful number, since it uses less digits than its factorization.

312122100131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10762831068.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 312122100131 its reverse (131001221213), we get a palindrome (443123321344).

The spelling of 312122100131 in words is "three hundred twelve billion, one hundred twenty-two million, one hundred thousand, one hundred thirty-one".

Divisors: 1 29 10762831039 312122100131