Base | Representation |
---|---|
bin | 100011011111000011110010… |
… | …0011011011010100000111111 |
3 | 1111221011112020002210122222222 |
4 | 1012332013210123122200333 |
5 | 311402432304104201301 |
6 | 3023503242412555555 |
7 | 122513535464052311 |
oct | 10676074433324077 |
9 | 1457145202718888 |
10 | 312131990693951 |
11 | 9050048553426a |
12 | 2b011330182bbb |
13 | 10521bc723582c |
14 | 57113aa0357b1 |
15 | 261440926831b |
hex | 11be1e46da83f |
312131990693951 has 2 divisors, whose sum is σ = 312131990693952. Its totient is φ = 312131990693950.
The previous prime is 312131990693927. The next prime is 312131990693953. The reversal of 312131990693951 is 159396099131213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312131990693951 - 214 = 312131990677567 is a prime.
It is a super-2 number, since 2×3121319906939512 (a number of 30 digits) contains 22 as substring.
Together with 312131990693953, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312131990693953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065995346975 + 156065995346976.
It is an arithmetic number, because the mean of its divisors is an integer number (156065995346976).
Almost surely, 2312131990693951 is an apocalyptic number.
312131990693951 is a deficient number, since it is larger than the sum of its proper divisors (1).
312131990693951 is an equidigital number, since it uses as much as digits as its factorization.
312131990693951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10628820, while the sum is 62.
The spelling of 312131990693951 in words is "three hundred twelve trillion, one hundred thirty-one billion, nine hundred ninety million, six hundred ninety-three thousand, nine hundred fifty-one".
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