Base | Representation |
---|---|
bin | 100011011111000011110110… |
… | …0101110110110000010101111 |
3 | 1111221011112120210221102001122 |
4 | 1012332013230232312002233 |
5 | 311402433100240131132 |
6 | 3023503304310531155 |
7 | 122513542105143413 |
oct | 10676075456660257 |
9 | 1457145523842048 |
10 | 312132130005167 |
11 | 905005471358aa |
12 | 2b01136a966abb |
13 | 10521c1a0614c4 |
14 | 57113c073ad43 |
15 | 26144165d5912 |
hex | 11be1ecbb60af |
312132130005167 has 2 divisors, whose sum is σ = 312132130005168. Its totient is φ = 312132130005166.
The previous prime is 312132130005149. The next prime is 312132130005169. The reversal of 312132130005167 is 761500031231213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312132130005167 - 230 = 312131056263343 is a prime.
Together with 312132130005169, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312132130005169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066065002583 + 156066065002584.
It is an arithmetic number, because the mean of its divisors is an integer number (156066065002584).
Almost surely, 2312132130005167 is an apocalyptic number.
312132130005167 is a deficient number, since it is larger than the sum of its proper divisors (1).
312132130005167 is an equidigital number, since it uses as much as digits as its factorization.
312132130005167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 35.
The spelling of 312132130005167 in words is "three hundred twelve trillion, one hundred thirty-two billion, one hundred thirty million, five thousand, one hundred sixty-seven".
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