Base | Representation |
---|---|
bin | 100011011111000100010100… |
… | …0010101100110010100100010 |
3 | 1111221011122011111122102200212 |
4 | 1012332020220111212110202 |
5 | 311402442122241121010 |
6 | 3023503551432414122 |
7 | 122513605640136056 |
oct | 10676105025462442 |
9 | 1457148144572625 |
10 | 312133130020130 |
11 | 90500a0a669951 |
12 | 2b0115a9847342 |
13 | 105220492a5433 |
14 | 571147748dc66 |
15 | 26144742bb505 |
hex | 11be228566522 |
312133130020130 has 8 divisors (see below), whose sum is σ = 561839634036252. Its totient is φ = 124853252008048.
The previous prime is 312133130020109. The next prime is 312133130020177. The reversal of 312133130020130 is 31020031331213.
It can be written as a sum of positive squares in 2 ways, for example, as 267462179941441 + 44670950078689 = 16354271^2 + 6683633^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 312133130020096 and 312133130020105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15606656500997 + ... + 15606656501016.
Almost surely, 2312133130020130 is an apocalyptic number.
312133130020130 is a deficient number, since it is larger than the sum of its proper divisors (249706504016122).
312133130020130 is a wasteful number, since it uses less digits than its factorization.
312133130020130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31213313002020.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 312133130020130 its reverse (31020031331213), we get a palindrome (343153161351343).
The spelling of 312133130020130 in words is "three hundred twelve trillion, one hundred thirty-three billion, one hundred thirty million, twenty thousand, one hundred thirty".
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