Base | Representation |
---|---|
bin | 101101011010111110100… |
… | …000011010000100100101 |
3 | 102001101201201110001120021 |
4 | 231122332200122010211 |
5 | 402120002130021313 |
6 | 10345531440435141 |
7 | 441336526560121 |
oct | 55327640320445 |
9 | 12041651401507 |
10 | 3121342423333 |
11 | aa3832474372 |
12 | 424b2b318ab1 |
13 | 198458b86ab4 |
14 | ab106644581 |
15 | 562d74b978d |
hex | 2d6be81a125 |
3121342423333 has 2 divisors, whose sum is σ = 3121342423334. Its totient is φ = 3121342423332.
The previous prime is 3121342423313. The next prime is 3121342423337. The reversal of 3121342423333 is 3333242431213.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2872204678564 + 249137744769 = 1694758^2 + 499137^2 .
It is a cyclic number.
It is not a de Polignac number, because 3121342423333 - 213 = 3121342415141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3121342423337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560671211666 + 1560671211667.
It is an arithmetic number, because the mean of its divisors is an integer number (1560671211667).
Almost surely, 23121342423333 is an apocalyptic number.
It is an amenable number.
3121342423333 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121342423333 is an equidigital number, since it uses as much as digits as its factorization.
3121342423333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 93312, while the sum is 34.
Adding to 3121342423333 its reverse (3333242431213), we get a palindrome (6454584854546).
The spelling of 3121342423333 in words is "three trillion, one hundred twenty-one billion, three hundred forty-two million, four hundred twenty-three thousand, three hundred thirty-three".
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