Base | Representation |
---|---|
bin | 101101011010111110100… |
… | …100010000101010000001 |
3 | 102001101201210100101001010 |
4 | 231122332210100222001 |
5 | 402120002404331340 |
6 | 10345531514231133 |
7 | 441336541264554 |
oct | 55327644205201 |
9 | 12041653311033 |
10 | 3121343433345 |
11 | aa3832aa4195 |
12 | 424b2b7254a9 |
13 | 19845914b737 |
14 | ab10682869b |
15 | 562d7618b80 |
hex | 2d6be910a81 |
3121343433345 has 8 divisors (see below), whose sum is σ = 4994149493376. Its totient is φ = 1664716497776.
The previous prime is 3121343433343. The next prime is 3121343433349. The reversal of 3121343433345 is 5433343431213.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3121343433345 - 21 = 3121343433343 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3121343433343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104044781097 + ... + 104044781126.
It is an arithmetic number, because the mean of its divisors is an integer number (624268686672).
Almost surely, 23121343433345 is an apocalyptic number.
It is an amenable number.
3121343433345 is a deficient number, since it is larger than the sum of its proper divisors (1872806060031).
3121343433345 is a wasteful number, since it uses less digits than its factorization.
3121343433345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 208089562231.
The product of its digits is 466560, while the sum is 39.
Adding to 3121343433345 its reverse (5433343431213), we get a palindrome (8554686864558).
The spelling of 3121343433345 in words is "three trillion, one hundred twenty-one billion, three hundred forty-three million, four hundred thirty-three thousand, three hundred forty-five".
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