Base | Representation |
---|---|
bin | 100011011111001000000010… |
… | …1001011000110011010000001 |
3 | 1111221012101211001000111222122 |
4 | 1012332100011023012122001 |
5 | 311403110013240000001 |
6 | 3023511353332014025 |
7 | 122514311120633411 |
oct | 10676200513063201 |
9 | 1457171731014878 |
10 | 312141130000001 |
11 | 90504345423165 |
12 | 2b013060a61315 |
13 | 10522a2280c333 |
14 | 57119d5b50641 |
15 | 26147917b0b1b |
hex | 11be4052c6681 |
312141130000001 has 8 divisors (see below), whose sum is σ = 315965509639104. Its totient is φ = 308332017346320.
The previous prime is 312141129999997. The next prime is 312141130000013. The reversal of 312141130000001 is 100000031141213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 312141130000001 - 22 = 312141129999997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (312141130000801) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3816705215 + ... + 3816786996.
It is an arithmetic number, because the mean of its divisors is an integer number (39495688704888).
Almost surely, 2312141130000001 is an apocalyptic number.
It is an amenable number.
312141130000001 is a deficient number, since it is larger than the sum of its proper divisors (3824379639103).
312141130000001 is a wasteful number, since it uses less digits than its factorization.
312141130000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7633492711.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 312141130000001 its reverse (100000031141213), we get a palindrome (412141161141214).
The spelling of 312141130000001 in words is "three hundred twelve trillion, one hundred forty-one billion, one hundred thirty million, one", and thus it is an aban number.
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