Base | Representation |
---|---|
bin | 1110001100011100110101… |
… | …10010010010001111010011 |
3 | 11002112001002222121020112002 |
4 | 13012032122302102033103 |
5 | 13042403011244310303 |
6 | 150215323134424215 |
7 | 6401101045050341 |
oct | 706163262221723 |
9 | 132461088536462 |
10 | 31214124213203 |
11 | 9a44921405618 |
12 | 360160b06206b |
13 | 145562cca6659 |
14 | 79cab3682991 |
15 | 391e3e981788 |
hex | 1c639ac923d3 |
31214124213203 has 2 divisors, whose sum is σ = 31214124213204. Its totient is φ = 31214124213202.
The previous prime is 31214124213199. The next prime is 31214124213247. The reversal of 31214124213203 is 30231242141213.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (30231242141213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31214124213203 - 22 = 31214124213199 is a prime.
It is not a weakly prime, because it can be changed into another prime (31214124213803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607062106601 + 15607062106602.
It is an arithmetic number, because the mean of its divisors is an integer number (15607062106602).
Almost surely, 231214124213203 is an apocalyptic number.
31214124213203 is a deficient number, since it is larger than the sum of its proper divisors (1).
31214124213203 is an equidigital number, since it uses as much as digits as its factorization.
31214124213203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 31214124213203 its reverse (30231242141213), we get a palindrome (61445366354416).
The spelling of 31214124213203 in words is "thirty-one trillion, two hundred fourteen billion, one hundred twenty-four million, two hundred thirteen thousand, two hundred three".
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